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I'll try posting this here..no love in the general forum

I have a new coil to install but it may have an internal resistor (as most do now days) so I need some clarification. Underneath the old coil is a wafer shaped disc that one of the coil wires ( left side-black) runs down to. A red wire then comes off the wafer/disc and goes to the replenishment lead wire (threaded connector at the bottom of the distributor assembly). Am I correct in assuming this disc is the old resistor ? If it is, and it is now not needed, do I just cut the wafer out and just splice the wires together so now the left (as you look at it/or forward) terminal wire atop the coil is now is directly connected to the red wire ?

Question answered.. Thank you to Charles

And the answer was.........?

Might be of help to others in the future.

Stu

Yes. The answer...

Ha!...I guess that would help...

According to Charles Talbert (who should know ) the M-37 coil was never fitted with an external ballast resistor..ie the disc I was referring to. But the 715 was. So apparently somehow that distributor got mixed up. SO, for my purposes, I need to simply cut the disc out of the loop and splice the wires back together with the positive coil terminal being fed by #12 (the lead from the harness) and the negative going to the points/condensor.

Thanks!
Philip